Dragon Horn max jump of 3

Just as a quick note, the lines that say C9 40 and C9 10 are probability lines. In C2/1828, the program chooses a random number between 00 and FF. If that number is below 40 (1/4), you'll execute a 3rd attack. If it's below 10 (1/16 chance), you'll execute a 4th attack. If you wanted the possibility of a 3rd attack, but wanted to make it rarer, you could just change C2/182E to a smaller number.

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Oh, it's just right above the first block of code. Just take off the C from the beginning and add 200 (hex) to account for the header.

That seems to have worked, thanks! I went ahead and reduced the chances of a 3rd attack to 10, or 1/16. I think that is a good setup now.