Users browsing this thread: 2 Guest(s)
FF6 Expansion Editor (FF6ExpED)
FFX does allow for multiple steals; each Steal slot is checked independently. You can steal between one or three items in one go, but you only get the one successful attempt.
Ok, I'm retarded.
are literally exactly the same and has exactly the same shortcoming.
I guess what I was trying to do was find a formula that effectively doubles the range of level difference where you still have a chance to Steal, while also staying close to an overall doubled Steal chance. Back to the drawing board for me.
In the meantime, my first suggestion (Attacker's Level * 2 + 100 - Target's Level) is the best I can come up with, since it allows Stealing at any relative level. Although it doesn't just double the Steal chance, it pretty much guarantees a Steal unless the level difference is more than 50.
Edit: D'oh. I guess what I'd like Sneak Ring to do is to simply give the Attacker 50 extra levels for the purpose of calculating Steal success. So pretty much just this:
Ok, I'm retarded.
Code:
(Attacker Level + 50 - Target Level) * 2
and
(Attacker Level * 2 + 100 - Target Level * 2)
I guess what I was trying to do was find a formula that effectively doubles the range of level difference where you still have a chance to Steal, while also staying close to an overall doubled Steal chance. Back to the drawing board for me.
In the meantime, my first suggestion (Attacker's Level * 2 + 100 - Target's Level) is the best I can come up with, since it allows Stealing at any relative level. Although it doesn't just double the Steal chance, it pretty much guarantees a Steal unless the level difference is more than 50.
Edit: D'oh. I guess what I'd like Sneak Ring to do is to simply give the Attacker 50 extra levels for the purpose of calculating Steal success. So pretty much just this:
Code:
StealValue = (Attacker Level + 100 - Target Level)
« Next Oldest | Next Newest »
Users browsing this thread: 2 Guest(s)